a^2+24^2=51^2

Solution for a^2+24^2=51^2 equation:

a^2+24^2=51^2

We move all terms to the left:

a^2+24^2-(51^2)=0

We add all the numbers together, and all the variables

a^2-2025=0

a = 1; b = 0; c = -2025;
Δ = b2-4ac
Δ = 02-4·1·(-2025)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-90}{2*1}=\frac{-90}{2}
=-45
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+90}{2*1}=\frac{90}{2}
=45
$